Ballast Calculation for Optimum Performance
Ballasting example:
We will use a tractor with the following features as an example:
Four front weights of 50 kg
Two rear weights of 55 kg
Two rear weights of 38.5 kg
12.4-24 front tires
18.4-30 rear tires
Weights on scale:
1450 kg front weight
1720 kg rear weight
Implement mounted to three-point hitch: 40x60 distribution (previous table).
Ballast necessary for
light load: 3870
kg (8532 Lb) (previous table).
Calculated front weight: 3870 x 0.40 = 1548 kg (3413 Lb)
Calculated rear weight: 3870 x 0.60 = 2322 kg (5119 Lb)
Necessary front weight: 1548 - 1450 = 98 kg (216 Lb)
Necessary rear weight:: 2322 - 1720 = 602 kg (1327 lb)
Each 50kg weight represents a weight increase of 65 kg on the front axle.
Front: 98 ÷ 65 = 1.5 - Add four weights of 50 kg to the front or ballast front tires with water.
For each solid front weight, subtract 15 kg from rear axle, by transfer.
Transfer: 2 x 15 = 30 kg (66 lb)
Necessary rear weight: 602 + 30 = 632 kg (1393 Lb)
Weight for rear tires: 632 ÷ 2 = 316 kg (697 lb)
18.4-30 tires with 40% of water weigh 176 kg according to tire weights table in this section.
Missing rear weight: 316 - 176 = 140 kg (309 lb)
Each external weight of tire weighs 38.5 kg
140 ÷ 38.5 = 3.6
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